Mid Function

Applies to: Access for Microsoft 365, Access 2019, Access 2016, Access 2013, Access 2010, Access 2007.

Returns a Variant (String) containing a specified number of characters from a string.

Syntax

Mid( string, start [, length ] )

The Mid function syntax has these arguments:

ArgumentDescription
stringRequired. string expression from which characters are returned. If string contains Null, Null is returned.
startRequired. Long. Character position in string at which the part to be taken begins. If start is greater than the number of characters in stringMid returns a zero-length string (“”).
lengthOptional. Variant (Long). Number of characters to return. If omitted or if there are fewer than length characters in the text (including the character at start), all characters from the start position to the end of the string are returned.

Remarks

To determine the number of characters in string, use the Len function.

Note: Use the MidB function with byte data contained in a string, as in double-byte character set languages. Instead of specifying the number of characters, the arguments specify numbers of bytes. For sample code that uses MidB, see the second example in the example topic.

Query examples

ExpressionResults
SELECT ProductID, Mid(ProductID,5) AS Expr1 FROM ProductSales;Returns the “ProductID” and the part of ProductID starting from character position 5 and displays the results in the column Expr1.
SELECT ProductID, Mid(ProductID,5,4) AS testMid FROM ProductSales;Returns the “ProductID” and the part of ProductID starting from character position 5, containing 4 characters and displays the results in the column testMid.

VBA examples

Note: Examples that follow demonstrate the use of this function in a Visual Basic for Applications (VBA) module. For more information about working with VBA, select Developer Reference in the drop-down list next to Search and enter one or more terms in the search box.

The first example uses the Mid function to return a specified number of characters from a string.

Dim MyString, FirstWord, LastWord, MidWords
MyString = "Mid Function Demo" ' Create text string.
FirstWord = Mid(MyString, 1, 3) ' Returns "Mid".
LastWord = Mid(MyString, 14, 4) ' Returns "Demo".
MidWords = Mid(MyString, 5) ' Returns "Function Demo".

The second example use MidB and a user-defined function (MidMbcs) to also return characters from string. The difference here is that the input string is ANSI and the length is in bytes.

Function MidMbcs(ByVal str as String, start, length)
MidMbcs = StrConv(MidB(StrConv(str, vbFromUnicode), _
start, length), vbUnicode)
End Function
Dim MyString
MyString = "AbCdEfG"
' Where "A", "C", "E", and "G" are DBCS and "b", "d",
' and "f" are SBCS.
MyNewString = Mid(MyString, 3, 4)
' Returns ""CdEf"
MyNewString = MidB(MyString, 3, 4)
' Returns ""bC"
MyNewString = MidMbcs(MyString, 3, 4)
' Returns "bCd"

See Also

String functions and how to use them

This information was compiled using information courtesy of © Microsoft 2020. All rights reserved.

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